solve for x of the following. (x-2/x+2)^2-4(x-2/x+2)+3=0 where x is not equal to -2
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x = -4 or -2
since, x-2/x+2 bracket square - 4(x-2/x+2) + 3 when evaluated forms a linear equation
i.e x square + 6x + 8 = 0
therefore, x=-4 or -2
since, x-2/x+2 bracket square - 4(x-2/x+2) + 3 when evaluated forms a linear equation
i.e x square + 6x + 8 = 0
therefore, x=-4 or -2
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by solving this equation x comes out to be -4
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