solve for x:-
p2x2+(p2-q2)x-q2=0
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▶ p²x² + (p² - q²)x - q² = 0
=> p²x² + p²x - q²x - q² = 0
=> p²x ( x + 1 ) - q² ( x + 1 ) = 0
=> ( x + 1 ) ( p²x - q² ) = 0
✳ ( x + 1 ) = 0
x = -1
✳ ( p²x - q² ) = 0
x = q²/p²
So, the value of x came to be -1 & q²/p²
@Altaf
=> p²x² + p²x - q²x - q² = 0
=> p²x ( x + 1 ) - q² ( x + 1 ) = 0
=> ( x + 1 ) ( p²x - q² ) = 0
✳ ( x + 1 ) = 0
x = -1
✳ ( p²x - q² ) = 0
x = q²/p²
So, the value of x came to be -1 & q²/p²
@Altaf
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