Question

Solve for X
Part 1
Please fast
I will mark the brainliest

Answer 1

Answer:

(i) x = 2, 7/29

(ii) x = 3

Step-by-step explanation:

11.

(i)

Given: (x² + 5x)/(3x² + 1) = 14/13

⇒ 13(x² + 5x) = 14(3x² + 1)

⇒ 13x² + 65x = 42x² + 14

⇒ -29x² + 65x - 14 = 0

⇒ 29x² - 65x + 14 = 0

⇒ 29x² - 7x - 58x + 14 = 0

⇒ x(29x - 7) - 2(29x - 7) = 0

⇒ (x - 2)(29x - 7) = 0

⇒ x = 2, 7/29.

(ii)

Given: (3x² + 5x + 8)/(5x² + 6x + 12) = (3x + 5)/(5x + 6)

⇒ (3x² + 5x + 8)(5x + 6) = (5x² + 6x + 12)(3x + 5)

⇒ 15x³ + 43x² + 70x = 15x³ + 43x² + 66x + 12

⇒ 15x³ + 43x² + 70x - 15x³ - 43x² - 66x - 12 = 0

⇒ 4x = 12

⇒ x = 3.

Hope it helps!

Answer 2

(i)

Given: (x² + 5x)/(3x² + 1) = 14/13

⇒ 13(x² + 5x) = 14(3x² + 1)

⇒ 13x² + 65x = 42x² + 14

⇒ -29x² + 65x - 14 = 0

⇒ 29x² - 65x + 14 = 0

⇒ 29x² - 7x - 58x + 14 = 0

⇒ x(29x - 7) - 2(29x - 7) = 0

⇒ (x - 2)(29x - 7) = 0

⇒ x = 2, 7/29.