solve for x
please answer it.
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Answer:
-1 ≤ x ≤ 3.
Step-by-step explanation:
l lx-1l + 2l ≤ 4
-4 ≤ lx-1l + 2 ≤ 4
-6 ≤ lx-1l ≤2
As lx-1l cannot be lesser than 0,
0 ≤ lx-1l ≤2
From this , 0≤ lx-1l (or) lx-1l ≤2
x=1 -2 ≤ x-1 ≤2
-1 ≤ x ≤ 3
Therefore, -1 ≤ x ≤ 3
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