Math, asked by pravinmanibhaipatel, 8 months ago

solve for x
please answer it.

Attachments:

Answers

Answered by rajdheerajcreddy
1

Answer:

-1 ≤ x ≤ 3.

Step-by-step explanation:

l lx-1l + 2l ≤ 4

-4 ≤ lx-1l + 2 ≤ 4

-6 ≤ lx-1l ≤2

As lx-1l cannot be lesser than 0,

0 ≤ lx-1l ≤2

From this ,    0≤ lx-1l     (or)      lx-1l ≤2

                    x=1                        -2 ≤ x-1 ≤2

                                                  -1 ≤ x ≤ 3

Therefore,   -1 ≤ x ≤ 3

                                                 

Similar questions