solve for x
please answer me
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Hope u like my process...
2 - logx = 2 log5 - 3log3 + log36
or, 2log5 - 3log3 +logx + log36 = 2
or, log 5² - log 3³ + logx + log36 =2
or, log ( 5² × 36 × x ÷3³) = 2
or, 25 × 4/3 × x = 10²
or, x = 10² × 3/100 = 3 _(answer) _
________________________
Hope this is ur required answer.
Proud to help you.
2 - logx = 2 log5 - 3log3 + log36
or, 2log5 - 3log3 +logx + log36 = 2
or, log 5² - log 3³ + logx + log36 =2
or, log ( 5² × 36 × x ÷3³) = 2
or, 25 × 4/3 × x = 10²
or, x = 10² × 3/100 = 3 _(answer) _
________________________
Hope this is ur required answer.
Proud to help you.
rakeshmohata:
e?
no
answer is 3
thn I hv to take base as 10
yup
I know..
now check it..
ok
it's not shown so I took base as e
but it's 10...
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