solve for x
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[tex]2^{3} (5^{0} + 3^{2x}) = 8 \frac{8}{27} \\
8(1 + 3^{2x}) = \frac{224}{27} \\
1 + 3^{2x} = \frac{28}{27} \\
3^{2x} = \frac{28}{27} - 1 = \frac{1}{27} = 3^{-3} \\
2x = -3 \\
x = - 1.5
[/tex]
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Hope u like my process..
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So, x = - 3/2 or - 1.5
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Hope this is ur required answer
Proud to help you
-------------------------------------
So, x = - 3/2 or - 1.5
-_-_-_-_-_-_-_-_-_-_- _-_-_-_-_-_-_
Hope this is ur required answer
Proud to help you
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