solve for x
please solve it...
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1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)=1/6
~(x-3)(x-4)+(x-1)(x-4)+(x-1)(x-2)/(x-1)(x-2)(x-3)(x-4)=1/6
~((use formula (x-a)(x-b) =x^2-(a+b)x+ab)))
~x^2-7x+12+x^2-5x+4+x^2-3x+2/(x-1)(x-2)(x-3)(x-4)=1/6
~3x^2-15x+18/(x-1)(x-2)(x-3)(x-4)=1/6
~3(x^2-5x+6)/(x-1)(x-2)(x-3)(x-4)=1/6
~3(x-2)(x-3)/(x-1)(x-2)(x-3)(x-4)=1/6
~3/(x-1)(x-4)=1/6
~3×6=(x-1)(x-4)×1
~18=(x-1)(x-4)
~ 18=x^2-5x+4
~x^2-5x-14=0
~(x-7)(x+2)=0
Therefore x=7 or x=-2
~(x-3)(x-4)+(x-1)(x-4)+(x-1)(x-2)/(x-1)(x-2)(x-3)(x-4)=1/6
~((use formula (x-a)(x-b) =x^2-(a+b)x+ab)))
~x^2-7x+12+x^2-5x+4+x^2-3x+2/(x-1)(x-2)(x-3)(x-4)=1/6
~3x^2-15x+18/(x-1)(x-2)(x-3)(x-4)=1/6
~3(x^2-5x+6)/(x-1)(x-2)(x-3)(x-4)=1/6
~3(x-2)(x-3)/(x-1)(x-2)(x-3)(x-4)=1/6
~3/(x-1)(x-4)=1/6
~3×6=(x-1)(x-4)×1
~18=(x-1)(x-4)
~ 18=x^2-5x+4
~x^2-5x-14=0
~(x-7)(x+2)=0
Therefore x=7 or x=-2
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hope this helps
Answered by
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Answer:
x=7. or x = -2 ............
is the value of x
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