solve for X .....plizz answer it
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Hey !!!!!
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According to the question,
16/x -1 = 15/x+1
16-x/x = 15/x+1. {Taking out LCM if 1}
Transposing x To RHS,
16-x = 15x/x+1. {Transposing x+1 to LHS}
(16-x) x+1 = 15x
(16-x) (x+1) = 15x
(Opening The Brackets)
16(x+1) - x ( x+1) =15x
16x + 16 - x^2 - x = 15x
16x-x + 16 - x^2 = 15x
15x + 16 - x^2 = 15x
16 - x^2 = 0 (Transposing 15x to LHS)
-x^2 = -16
x^2 = 16
x = √16
x = √ 8×2
x = √ 2×2×2×2
x = 4
Hence,
The Value of x is 4
______________________________
Thanks....!!!
Hope This Helps.....!!!
☺️☺️
_____________________________
According to the question,
16/x -1 = 15/x+1
16-x/x = 15/x+1. {Taking out LCM if 1}
Transposing x To RHS,
16-x = 15x/x+1. {Transposing x+1 to LHS}
(16-x) x+1 = 15x
(16-x) (x+1) = 15x
(Opening The Brackets)
16(x+1) - x ( x+1) =15x
16x + 16 - x^2 - x = 15x
16x-x + 16 - x^2 = 15x
15x + 16 - x^2 = 15x
16 - x^2 = 0 (Transposing 15x to LHS)
-x^2 = -16
x^2 = 16
x = √16
x = √ 8×2
x = √ 2×2×2×2
x = 4
Hence,
The Value of x is 4
______________________________
Thanks....!!!
Hope This Helps.....!!!
☺️☺️
Anonymous:
Also, This Satisfies The Eq. x is not equal to 0 & -1
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