Question

solve for x
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Answer 1

$Answer \: \\ \\ Given \: \: Question \: \: Is \: \\ \\ \\ 2 {}^{(2x + 3)} =8 {}^{(5x + 2)} \\ \\ 2 {}^{2x} \times 2 {}^{3} = 8 {}^{5x} \times 8 {}^{2} \\ \\ 2 {}^{2x} \times 8 = 8 {}^{5x} \times 8 {}^{2} \\ \\ \frac{2 {}^{2x} }{8 {}^{5x} } = \frac{8 {}^{2} }{8} \\ \\ \frac{2 {}^{2x} }{2 {}^{3 \times 5x} } = 8 {}^{2} \times 8 {}^{ - 1} \\ \\ \frac{2 {}^{2x} }{2 {}^{15x} } = 8 \\ \\ 2 {}^{2x} \times 2 {}^{ - 15x} = 2 {}^{3} \\ \\ 2 {}^{ - 13x} = 2 {}^{3} \\ \\ Now \: \: compare \: \: powers \: of \: 2 \: \: we \: \: have \\ \\ - 13x = 3 \\ \\ - x = \frac{3}{13} \\ \\ x = \frac{ - 3}{13}$

Answer 2

Answer:

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