solve for x ....
plzzz do fast
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Hope it helps you........
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Hope u like my process..
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![{2}^{3} ( {5}^{0} + {3}^{2x} ) = 8 \frac{8}{27} \\ or. \: {2}^{3} (1 + {3}^{2x} ) = 8 + \frac{8}{27} \\ or. \: {2}^{3} + {2}^{3} \times {3}^{2x} = {2}^{3} + {2}^{3} \times {3}^{ - 3} \\ \\ thus \: by \: comparing \: we \: get \: .. \\ 2x = - 3 \\ or. \: x = - \frac{3}{2} {2}^{3} ( {5}^{0} + {3}^{2x} ) = 8 \frac{8}{27} \\ or. \: {2}^{3} (1 + {3}^{2x} ) = 8 + \frac{8}{27} \\ or. \: {2}^{3} + {2}^{3} \times {3}^{2x} = {2}^{3} + {2}^{3} \times {3}^{ - 3} \\ \\ thus \: by \: comparing \: we \: get \: .. \\ 2x = - 3 \\ or. \: x = - \frac{3}{2}](https://tex.z-dn.net/?f=+%7B2%7D%5E%7B3%7D+%28+%7B5%7D%5E%7B0%7D++%2B++%7B3%7D%5E%7B2x%7D+%29+%3D+8+%5Cfrac%7B8%7D%7B27%7D++%5C%5C+or.+%5C%3A++%7B2%7D%5E%7B3%7D+%281+%2B++%7B3%7D%5E%7B2x%7D+%29+%3D+8+%2B++%5Cfrac%7B8%7D%7B27%7D++%5C%5C+or.+%5C%3A++%7B2%7D%5E%7B3%7D++%2B++%7B2%7D%5E%7B3%7D++%5Ctimes++%7B3%7D%5E%7B2x%7D++%3D++%7B2%7D%5E%7B3%7D++%2B++%7B2%7D%5E%7B3%7D++%5Ctimes++%7B3%7D%5E%7B+-+3%7D++%5C%5C++%5C%5C+thus+%5C%3A+by+%5C%3A+comparing+%5C%3A+we+%5C%3A+get+%5C%3A+..+%5C%5C+2x+%3D++-++3+%5C%5C+or.+%5C%3A+x+%3D+++-+%5Cfrac%7B3%7D%7B2%7D+)
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Hope this is ur required answer
Proud to help you
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Hope this is ur required answer
Proud to help you
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