Math, asked by richasarma88, 1 year ago

Solve for x=pqx2-(p2+q2)x+pq=0

Answers

Answered by knjroopa
14

Answer:

Step-by-step explanation:

Given  

Solve for x = pqx2-(p2+q2)x+pq=0

ANSWER

Simplifying we get

 Pqx^2 – p^2 x – q^2 x + pq = 0

 Px(q x – p) – q(q x – p) = 0

 (q x – p)(p x – q) = 0

Now q x – p = 0

       q x = p

     x = p/q

Also p x – q = 0

      p x = q

       x = q/p

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