Solve for x: root 2x^2 + 7x + 5root2 = 0
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root 2x^ 2 +7x +5 root 2 =0
root 2 x^2 + 2x +5x +5 root 2 =0
root 2x(x +root 2 )+ 5 (x+ root 2) =0
=root 2x+5=0 and x + root 2 =0
therefore, x= -5/root 2 and x= - root2
root 2 x^2 + 2x +5x +5 root 2 =0
root 2x(x +root 2 )+ 5 (x+ root 2) =0
=root 2x+5=0 and x + root 2 =0
therefore, x= -5/root 2 and x= - root2
ektapasrichaosq70r:
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thank you for your answer it helped!:)
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