Question

Solve for x: root 2x^2 + 7x + 5root2 = 0
Plz ans

Answer 1

√2x^2+5x+2x+5√2=0
x(√2x+5)+√2(√2x+5)=0
(√2x+5)(x+√2)=0
x=-5/√2or-√2
x=-5√2/2. or .-√2
is your answer

Answer 2

√2 x2 + 7x + 5√2 = 0
Similarly multiply √2 with 5√2 and we get 10

Pairs of 10 are

1*10 = 10 sum 1+ 10 = 11


2*5 = 10 sum 2+ 5 = 7

So our required pair is 2 and 5

√2 x2 + 5x + 2x + 5√2 = 0

x (√2x + 5) + √2(√2x + 5) = 0

(√2x + 5)(x + √2) = 0

√2x + 5 = 0 and x + √2 = 0

x = –5/√2 and x = –√2

–5/√2 and –√2 are our required root of quadratic equation.

Hope it's helpful to uh.

Thankyou