solve for x root 3x square - 2root 2x - 2root 3 equal to 0
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√3x² - 2√2x - 2√3 = 0
=> √3x² - 3√2x + √2x - 2√3 = 0
=> √3x( x - √6) + √2( x - √6) = 0
=> ( x - √6)( √3x + √2 ) = 0
=> x - √6 = 0 or, √3x + √2 = 0
=> x = √6
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