Math, asked by mahwish23, 7 months ago

solve for x: root a÷b=(b÷a) ¹-³^x

Answers

Answered by princegupta99270
2

Step-by-step explanation:

given root under a/b =(b/a)^1-3x

As (a/b)^1/2=(b/a)^1-3x

Then (b/a)^-1/2 =(b/a)^1-3x

Then solve for x in

-1/2=1-3x

You get x =1/2

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