Math, asked by keerti0615, 9 months ago

Solve for x ;root of√3x^2+x+5=x-3

Answers

Answered by MYMINDMYWEAPON
2

Answer:

 \sqrt{3x ^{2}  + x + 5 }  = x - 3

3x^2+x+5= (x -3)^2

3x ^2 + x+5=x^2+9-6x

3x^2-x^2+x+6x+5-9=0

2x^2+7x-4

FACTORISE

2X^2+8X-X-4

2X^2(X+4) -1(X+4)

X=-4(OR)X=1/2

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