Math, asked by raghavkanodia5, 5 months ago

Solve for x: root2 x2 + 3x - 9 root2 = 0​

Answers

Answered by Anonymous
4

 \sqrt{2}  \times 2 + 3x - 9 \sqrt{2}  = 0

2 \sqrt{2}   - 9 \sqrt{2}  + 3x = 0

 - 7 \sqrt{2}  + 3x = 0

3x = 7 \sqrt{2}

x = 7 \sqrt{2}  \div 3

hope u got ur answer........

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