solve for x : root3x^2+10x+7root3=0
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Answered by
8
root3x^2+10x+7root3=0
root3x^2+7x+3x+7root3=0
x(root3x+7)+root3(root3x+7)=0
(root3x+7)(x+root3)=0
root3x+7=0
x=-7/root3
x+root3=0
x=-root3
root3x^2+7x+3x+7root3=0
x(root3x+7)+root3(root3x+7)=0
(root3x+7)(x+root3)=0
root3x+7=0
x=-7/root3
x+root3=0
x=-root3
Answered by
9
hope it helps.......✍
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