Math, asked by bhaktipatel9258, 1 year ago

Solve for x : (sec^269°-cot^221°upon 3)-2 upon 3 sin 90°+3 tan^264° upon cot^226°=x upon 3

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Answered by kartikkagra

0

Ususjsjsjsjsjb cot tan susjsjsjsjusjsjsn72727

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