Solve for x: tan -1 2x + tan -1 3x = npi + 3pi/4
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tan^-1 (2x)+tan^-1 (3x)=npi+3pi/4
tan^-1 {(2x+3x)/(1-6x^2)}=npi.+3pi /4
5x/(1-6x^2)=tan (npi.+3pi/4)
if n=1
you got x=1,-1/6
but x not equal -1/6
also put n=2
and find it but condition apply
tan^-1 {(2x+3x)/(1-6x^2)}=npi.+3pi /4
5x/(1-6x^2)=tan (npi.+3pi/4)
if n=1
you got x=1,-1/6
but x not equal -1/6
also put n=2
and find it but condition apply
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14
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