Solve for x:tan−1(x+1)+tan−1x+tan−1(x−1)=tan−13.
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Answer:
Hello,
here, after solving the above inverse trigonometric function eqn.
we get a cubic eqn i.e.
x^3-9x^2-4x+6=0
Now , solving the cubic eqn we get:-
so,x=-1
Thank you !!!
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-----> Imop. formula for this question is
tan^-1 (x)+tan^-1 (y)
= tan^-1 {(x+y)/(1-xy))} .
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