solve for x:
tan inverse(2+x) + tan inverse(2-x) =tan inverse 2/3
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tan inv (2+x) + tan inv (2-x)
= tan inv { (2+x+2-x)/( 1 - (2+x)(2-x) )}
= tan inv {4/(x²-3)}= tan inv 2/3
= 4/(x²-3)=2/3
6 =x²-3
x²=9
x=±3
= tan inv { (2+x+2-x)/( 1 - (2+x)(2-x) )}
= tan inv {4/(x²-3)}= tan inv 2/3
= 4/(x²-3)=2/3
6 =x²-3
x²=9
x=±3
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