Question

Solve for x:tan inverse (x+1)+tan inverse of(x-1) =tan inverse (8/31)

Answer 1

Answer:

x=1/4 or -8

Step-by-step explanation:

tan inverse (x+y/1-xy)

tan inverse [x+1+x-1/1-(x-1)(x+1)] = tan inverse 8/31

tan inverse(2x/1-x^2+1) = tan inverse 8/31 [(x-1)(x+1)=x^2-1]

2x/2-x^2=8/31

16-8x^2=62x

8x^2+62x-16=0

divide by 2

4x^2+31x-8=0

4x^2+32x-x+8=0

4x(x+8)-1(x+8)=0

(x+8) (4x-1)=0

x+8=0 or 4x-1=0

x=-8 or x=1/4