Question

solve for x .
$3 {x}^{2} - 2 \sqrt{6} + 2$
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Answer 1

Answer:

❣ ANSWER ❣

✡ ROCKY HERE ✌

$3 {x}^{2} - 2 \sqrt{6} + 2 = 0 \\ 3 {x}^{2} - \sqrt{6} - \sqrt{6} + 2 = 0 \\ \sqrt{3x} ( \sqrt{3x} - \sqrt{2}) - \sqrt{2} ( \sqrt{3x} - \sqrt{2} ) = 0 \\ ( \sqrt{3x} - \sqrt{2} )( \sqrt{3x} - \sqrt{2} ) = 0 \\ \\ x = \sqrt{ \frac{2}{3} } \: \: \: \: and \: \: \: \: \: x = \sqrt{ \frac{2}{3} }$

✴HAPPY TO HELP

Answer 2

Answer:

Solution:

3x² - 2√6 + 2 = 0

3x² - √6 - √6 + 2 = 0

√3x(√3x - √2) - √2(√3- √2) = 0

(√3 - √2) (√3 - √2) = 0

$x = \sqrt{ \frac{2}{3} }$

Hope it will be helpful :)