Math, asked by kshitij200399, 11 months ago

Solve for x :

 {3}^{x}  + x - 2 = 0

Answers

Answered by Anonymous
4

SOLUTION ☺️

  =  =  > {3x}^{2}  + x - 2 = 0 \\  \\  =  =  >  {3x}^{2}  + (3x - 2x) - 2 = 0 \\  \\  =  =  >  {3x}^{2}  + 3x - 2x - 2 = 0 \\  \\  =  =  > 3x(x + 1)  - 2(x  + 1)  = 0\\  \\  =  =  > (x   + 1)(3x  - 2) = 0 \\  \\  =  =  > if \: (x + 1) = 0 \\  \\  =  =  > x =  - 1 \\  \\  =  =  > if \: (3x - 2) = 0 \\  \\  =  = > 3x = 2 \\  \\  =  =  > x =  \frac{2}{3}

HOPE IT HELPS ✔️


kshitij200399: see the question properly
kshitij200399: you have misunderstood it
kshitij200399: have you got it
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