Question

solve for x :
$9 {x}^{2} - 6ax + ( {a}^{2} - {b}^{2}) = 0$
Pls solve it fast.. ​

Answer 1

Here is ur answer..hope this helps if so plz mark as brailiest.

Answer 2

$\huge\mathfrak\yellow{Answer}$

9x² - 6ax - (a² - b²) = 0

9x² - 3(a - b)x - 3(a - b)x - (a² - b²) = 0

3x[ 3x - (a + b)] - (a - b)[3x - (a + b) = 0

[3x - (a - b)] = 0. [3x - (a + b)] = 0

X = (a - b) / 3. X = (a + b) / 3