Question

solve for x
$\frac{1}{x + a} + \frac{1}{x + 2a} + \frac{1}{x + 3a} = \frac{3}{x}$
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Answer 1

$x^2+5ax+6a^2+x^2+4ax+$ $3a^2+x^2+3ax+2a^2÷(X+a)$

$(X+2a)+(X+3a)=3/x$

$3x^2+12ax+11a^2÷(X+a)$

$(X+2a)(X+3a)=3/x$

$3x^3+12ax^2+11a^2x÷$

$3(X+a)(X+2a)(X+3a)$

$3x^3+12ax^2+11a^2x÷3x^3$ $+33a^2x+18ax^2+18a^3$

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Answer 2

Hola Mate

refer to the attachment: