CBSE BOARD X, asked by shantalohakare050, 1 month ago

solve for x;
 \frac{x - 1}{x - 2}  +  \frac{x - 3}{x - 4}  =  \frac{10}{3}
where (x is not equal to 2,4)​

Answers

Answered by vishalaryan022
1

Answer:

Note: dividing by a fraction is the same as multiplying by the reciprocal of the fraction.

In some cases of simplifying an algebraic expression, the expression will be a fraction. For example,

\[\frac{x^{2} + 3x}{x + 3}\]

has a quadratic binomial in the numerator and a linear binomial in the denominator. We have to apply the different factorisation methods in order to factorise the numerator and the denominator before we can simplify the expression.

\begin{align*} \frac{{x}^{2} + 3x}{x + 3} & = \frac{x\left(x + 3\right)}{x + 3}\\ & =x \qquad \qquad \left(x\ne -3\right) \end{align*}

If \(x=-3\) then the denominator, \(x + 3 = 0\) and the fraction is undefined.

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