Question

⠀⠀⠀⠀⠀
✭ Solve for 'x' :
⠀⠀⠀
$\it{\dfrac{x+3}{x-2}-\dfrac{1-x}{x}=4\dfrac{1}{4}}$​

Answer 1

Step-by-step explanation:

(x+3)/(x-2)-(1-x)/x=4 1/4

=>x(x+3)-(x-2)(1-x)/x(x-2)=17/4

=> x^2+3x-(x-2-x^2+2x)/x(x-2)=17/4

=> x^2+3x-x+2+x^2-2x/x(x-2)=17/4

=> 2x^2+2/x(x-2)=17/4

=> 17x(x-2)=8x^2+8

=> 17x^2-34x-8x^2-8=0

=> 9x^2-34x-8=0

=> 9x^2-36x+2x-8=0

=> 9x(x-4)+2(x-4)=0

=> (x-4)(9x+2)=0

=> x-4=0

=> x=4

again,

9x+2=0

=> 9x= -2

=> x= -2/9