solve for x:
![\sqrt{2x \: + \: 9 \: \: \: + \: x \: = \: 13} \sqrt{2x \: + \: 9 \: \: \: + \: x \: = \: 13}](https://tex.z-dn.net/?f=+%5Csqrt%7B2x+%5C%3A++%2B++%5C%3A+9+%5C%3A++%5C%3A++%5C%3A++%2B++%5C%3A+x+%5C%3A++%3D++%5C%3A+13%7D+)
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➡️ 2x + 9 + x = 13.
Or, 3x = 4.
Or, x = 4/3.
That's it..
michal2:
how u this is only correct answer
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