Question

Solve for x:
$x ^{2} + (3 - 2a)x - 6a = 0$
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Answer 1

Answer:

=>x²+(3-2a)x-6a=0

=>x²+3x-2ax-6a=0

=>x(x+3)-2a(x+3)=0

=>(x+3)(x-2a)=0

Either, or,

x+3=0 x-2a=0

x=-3 x=2a