Math, asked by susiekk, 1 year ago

Solve for x.
 {x}^{2}  + 5x - ( {a}^{2}  + a - 6) = 0 \:  \:  \: .

Answers

Answered by Anonymous
3
 \huge{ \mathbb{QUESTION:-}}


x²+5x-(a²+a-6)=0



 \huge{ \mathbb{SOLUTION:-}}




\bold{\mathsf{Method\: of \: Solution}}

=> x²+5x-(a²+a-6)=0



=> x²+5x-{(a²+3a-2a-6)}=0



=>x²+5x-[{a(a+3)-2(a+3)}]=0



=> x²+5x-(a-2)(a+3)=0



=>x²+(a+3)x-(a-2)x-(a-2)(a+3)=0



=> x[x+(a+3)-(a-2)[x+(a+3)]=0



=> [x+(a+3)]=0


=> x=-(a+3)



[x-(a-2)]=0


=> x=a-2


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susiekk: OK leave it but thanks again
Anonymous: hmm
susiekk: wait I dint get the 5th step
Anonymous: I had split into Product and sum
susiekk: but where how have changed that 5x away?
susiekk: 5x changed into what??
kajal1902: may i tell you where 5x has gone
kajal1902: we can write 5x = x(a+3)-(a-2)x as ax+3x -ax+2x =5x
susiekk: thanks kajal1902
Anonymous: :)
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