Math, asked by boss238, 1 year ago

solve for x
 {x}^{2}   +   {x}^{4 }  = 90

Answers

Answered by gaurav2013c
0
x^2 + x^4 = 90

=> x^4 + x^2 - 90 = 0

Let x^2 = a

=> a^2 + a - 90 = 0

=> a^2 + 10a - 9a - 90 = 0

=> a (a +10) - 9( a +10) = 0

=> (a+10)(a-9) = 0


a = - 10 and 9

Neglecting negative value,

a = 9

=> x^2 = 9

=> x = +3 and - 3


Answered by siddhartharao77
4
Given Equation is x^2 + x^4 = 90

x^2 + x^4 - 90 = 0

x^4 + x^2 - 90 = 0

x^4 - 9x^2 + 10x^2 - 90 = 0

x^2(x^2 - 9) + 10(x^2 - 9) = 0

(x^2 - 9)(x^2 + 10) = 0

x = 3, -3 (or)  \sqrt{10}i, - \sqrt{10} i


Hope this helps!

siddhartharao77: :-)
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