Question

Solve for x: under root 6x+7 - root(2x-2) =3

Answer 1

Hi,

Sqrt (6x +7) - (2x - 7 ) = 0

sqrt ( 6x + 7 ) = ( 2x - 7 )

Squreing bothsides

( sqrt ( 6x + 7 ))^2 = ( 2x - 7 )^2

6x + 7 = 4x^2 -28x +49

0 = 4x^2 -28x -6x +49 - 7

4x^2 -34x +42 = 0

Divide each term with 2

2x^2 - 17x +21 = 0

2x^2 - 14x - 3x +21 = 0

2x ( x - 7 ) - 3( x - 7 ) = 0

( x - 7 ) ( 2x - 3 ) = 0

x - 7 = 0 or 2x - 3 = 0

x = 7 or 2x = 3

x = 7 or x = 3/2

I hope this will help you .