Question

Solve for x unvalid answers would be reported​

Answer 1

Please see the attachment for your answer.

Hope it helps

Answer 2

Step-by-step explanation:

We have,

$\frac{x}{x + 1} + \frac{x + 1}{x} = \frac{34}{15}$

$\implies \frac{ {x}^{2} + {(x + 1)}^{2} }{(x + 1)x} = \frac{34}{15}$

$\implies \frac{ 2{x}^{2} + 2x + 1}{x^{2} + x} = \frac{34}{15}$

$\implies \frac{ 30{x}^{2} + 30x + 15}{34x^{2} + 34x} = 1$

$\implies30 {x}^{2} + 30x + 15 = 34 {x}^{2} + 34x$

$\implies4 {x}^{2} + 4x - 15 = 0$

$\implies4 {x}^{2} + 10x - 6x- 15 = 0$

$\implies2x(2x + 5) - 3(2x + 5) = 0$

$\implies(2x + 5)(2x - 3) = 0$

$\implies \: x = - \frac{5}{2} \: \: or \: x = \frac{3}{2}$