Math, asked by ravirani522, 10 months ago


Solve for x; where 0º < x < 90
sin2 x + cos2 30º =5/4​

Answers

Answered by majjis444
0

Answer:

the formula for this is sin^/cos

Answered by umiko28
2

Answer:

\huge\underline{ \underline{ \red{your \: \: answer}}}

\large\boxed{ \fcolorbox{red}{purple}{hope \: it \: help \: you}}

Step-by-step explanation:

\sf\purple{ {sin}^{2}x +  {cos}^{2}30°=  \frac{5}{4}} \\ \sf\purple{ =  &gt;  {sin}^{2}x =  \frac{5}{4} -  {cos}^{2}30°   } \\ \sf\purple{ =  &gt;  {sin}^{2}x =  \frac{5}{4}  -  { (\frac{ \sqrt{3} }{2} }^{2})} \\ \sf\purple{ =  &gt;  {sin}^{2}x =  \frac{5}{4}  -  \frac{3}{4}  } \\ \sf\purple{  =  &gt; {sin}x =  ±\sqrt{\frac{2}{4} } } \\ \sf\purple{ =  &gt;  {sin}x = {\frac{1}{\sqrt2} }} \\ \\ \sf\purple{=&gt;sinx = sin45°} \\ \sf\purple{=&gt;x = 45°}

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