Math, asked by susiekk, 1 year ago

solve for x :-
.. Will surely mark as brainliest!

Attachments:

Answers

Answered by Anonymous
3
(ax - a^2 + bx - b^2)/ ( x-b)( x-a)= 2

ax - a^2 + bx - b^2 = 2( x- b)( x-a)

ax - a^2 + bx - b^2 = 2( x^2 - ax -bx + ab)

ax -a^2 + bx - b^2 = 2x^2 - 2ax - 2bx + 2ab

ax+ bx + 2ax + 2bx - 2x ^2 - a^2 - b^2 - 2ab = 0

3ax + 3bx - 2x^2 - ( a+b)^2 = 0

2x^2 - 3x( a+b) + ( a+b)^2 = 0

2x^2 - 2x( a+b) - x( a+b)+ ( a+b)^2 = 0

2x( x - ( a+b)) - (a+b)( x - ( a+b)) = 0

(2x - ( a+b)) ( x- (a+b)) = 0

2x= a+ b,, x= a+b

x= (a+b)/2 , a+b

susiekk: but will you plzz solve in a copy and send the answer by clicking its pic.. m not able to understand the ^signs?
Similar questions