Math, asked by chandeshwar631, 9 months ago

solve for x. write the samller solution first, and the largest solution second 4x^2+72x+320=0​

Answers

Answered by lasygout
1

Answer:

x=8 or x=10

Step-by-step explanation:

Use the quadratic formulax = \frac{-b +-  \sqrt[]{b^{2}  -4ac} }{2a}

a is the number before x^2

b is the number before x

and c is the remaining number

a=4; b=72; c=320

However, all these can be divided by 4

a=1; b=18; c=80

Sub all these into the formula.

I like to start with the 2a denominator

2a = 2(1) = 2

(Im doing these piece by piece otherwise it gets a bit messy)

Next: 4ac  -- 4(1)(80) = 320

b^2 = 18^2 = 324

324 - 320 = 4

So now we are left with \frac{-b+- \sqrt{4} }{2}

simplified: \frac{18+-2}{2}

So our answers are 10 and 8

Answered by wensoo0327
1

Answer:

Upper answer is wrong answer is -10,-8

Step-by-step explanation: If you want to know the truth just insert 8 or 10 in the equation

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