Solve for x: (|x|-1) / (|x|-2) > 5
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Answer:
x−1∣−5∣≥2
((x−1)−5)∈(−∞,−2)∪(2,0)
−∞<∣x−1∣−5≤−2 2≤∣x−1∣−5<∞
−∞<∣x−1∣≤3 7≤∣x−1∣<∞
⇒∣x−1∣≤3 ⇒∣x−1∣≥7
−3≤(x−1)≤3 ⇒(x−1)∈(−∞,−7)∪[7,∞]
⇒
−2≤x≤4
x∈(−∞.−6)∪[8,∞]
∴x∈[−∞,−6]∪[−2,4]∪[8,∞]
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