Math, asked by kunnalshrma, 7 months ago

solve for x: x−1 / x + x /x−1 = 61 30 ; x ≠ 0, 1​​

Answers

Answered by saaho91
0

Answer:

STEP

1

:

61

Simplify ——

30

Equation at the end of step

1

:

x 1 61

(((—+1)+x)+—)-—— = 0

x x 30

STEP

2

:

1

Simplify —

x

Equation at the end of step

2

:

x 1 61

(((— + 1) + x) + —) - —— = 0

x x 30

STEP

3

:

x

Simplify —

x

Equation at the end of step

3

:

1 61

(((1 + 1) + x) + —) - —— = 0

x 30

Answered by EthicalElite
37

\red{\bold{\underline{\underline{Question᎓}}}}

 \sf \frac{x−1}{x} + \frac{x }{x−1} = \frac{61}{30}; x ≠ 0, 1

\huge\tt\underline\blue{Answer}

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 \sf ➜ \: \frac{x-1}{x} + \frac{x}{x-1} = \frac{61}{30}

 \sf ➜ \: \frac{(x-1)(x-1) + (x × x)}{x(x-1)} = \frac{61}{30}

 \sf ➜ \: \frac{x(x-1) -1(x-1) + x²}{x²-x} = \frac{61}{30}

 \sf ➜ \: \frac{x²-x -x+1 + x²}{x²-x} = \frac{61}{30}

 \sf ➜ \: \frac{2x²-2x+1}{x²-x} = \frac{61}{30}

 \sf ➜ \: (2x²-2x+1)30 = 61(x²-x)

 \sf ➜ \: 60x²- 60x + 30 = 61x² - 61x

 \sf ➜ \: 60x²- 60x + 30 - 61x² + 61x = 0

 \sf ➜ \: -x² + x + 30 = 0

 \sf ➜ \: -x² + x + 30 = 0

 \sf ➜ \: -x² + 6x - 5x + 30 = 0

 \sf ➜ \: -x(x - 6) - 5(x - 6) = 0

 \sf ➜ \: (-x - 5)(x - 6) = 0

___________________________

 \sf -x -5 = 0

 \sf -x = 5

 \boxed{\sf x = -5}

___________________________

 \sf x -6 = 0

 \boxed{\sf x = 6}

___________________________

 \sf \red{Therefore, \: value \: of \: x \: is \: 6 \: or \: -5}

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