Solve for x (x^2+1/x^2)-3(x-1/x)
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(² ² + 1 - ) - 3 (₁ - 1) - 2 - 0 x² 2
Let x y squaring on both sides 1
x²
⇒ x² +
1
=y² + 2
Putting these values in the given equation
(y² + 2) − 3y - 2 = 0 y²-3y = 0 then y = 0 or y = 3
=> y(y - 3) = 0
if y = 0 or y-3=0
1
0
or x
x² ↑ ง 1 0 x² - or 1 = 3 X
⇒ x² − 1 = 0 or x²-3x-1=0
-( ⇒ (x + 1)(x − 1) = 0 or x =
=> x = -1 and x = 1 3 ± √13 2 or x
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