Math, asked by kasp5500, 2 days ago

Solve for x (x^2+1/x^2)-3(x-1/x)

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Answered by saritadwivedigtk
1

(² ² + 1 - ) - 3 (₁ - 1) - 2 - 0 x² 2

Let x y squaring on both sides 1

⇒ x² +

1

=y² + 2

Putting these values in the given equation

(y² + 2) − 3y - 2 = 0 y²-3y = 0 then y = 0 or y = 3

=> y(y - 3) = 0

if y = 0 or y-3=0

1

0

or x

x² ↑ ง 1 0 x² - or 1 = 3 X

⇒ x² − 1 = 0 or x²-3x-1=0

-( ⇒ (x + 1)(x − 1) = 0 or x =

=> x = -1 and x = 1 3 ± √13 2 or x

please mark it brainliest

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