Question

solve for x: x^2-2(a^2+b^2)x+(a^2-b^2)^2=0​

Answer 1

Answer:

x² - 2( a² + b² )x + ( a² - b² )² = 0☣a = 1☣b = -2a² - 2b²☣c ... Find the roots of the equation x2-2(a2+b2)x+(a2-b2)2 = 0. 2.