Question

solve for x : x^2+2(m-1)x+(m+1)=0​

Answer 1

Answer:

x₁ = - m + 1 + 2√m(m - 3)

x₂ = - m + 1 - 2√m(m - 3)

Step-by-step explanation:

x² + 2(m-1)x + (m+1) = 0​

x² + (2m-2)x + (m+1) = 0

x = (-(2m-2) ± √((2m-2)² -4(1)(m+1))) / 2(1)

x = (-(2m-2) ± √((4m²- 8m + 4) -4(m+1))) / 2

x = (-(2m-2) ± √(4m²- 8m + 4 - 4m - 4)) / 2

x = (-(2m-2) ± √(4m²- 12m)) / 2

x = (-2(m-1) ± √4(m²- 3m)) / 2

x = - m + 1 ± 2√m(m - 3)

x₁ = - m + 1 + 2√m(m - 3)

x₂ = - m + 1 - 2√m(m - 3)