Question

solve for x : x^2+2(m-1)x+(m+1)=0​

Answer 1

Answer:

Hey there,

That's a good question. So let's start from the very beginning!!!

EQUATION-x²+x(2m-2)+(m+5)

If the roots are to be real and equal then the value of discriminant(D) is to be 0.

D=0

(2m-2)²-4(m+5)=0

4m²-12m-16=0

Taking 4 as common, we get-

m²-3m-4=0

m²+4m-m-4=0

m(m+4)-1(m+4)=0

(m-1)(m+4)=0

Therefore m=1 or m=-4

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