Question

solve for x: x^2-9/X+3=4/7​

Answer 1

sorry it don't know what does ^ reffers

Answer 2

Answer:

$x=\dfrac{25}{7}$

Step-by-step explanation:

As we have given in the question that we need to solve for x, We had given 1 fraction which is$\dfrac{x^{2}-9}{x+3}=\dfrac{4}{7}$

We know the identity of (a+b)(a-b)=$a^{2}-b^{2}$

Here we apply this identity in numerator it should be written as

$x^{2}-9=(x+3)(x-3)$

So we remake our equation i.e.$\dfrac{(x+3)(x-3)}{x+3}=\dfrac{4}{7}$

x+3 would be cancelled out from denominator, So the remaining equation would be

=[tex]x-3=\dfrac{4}{7}[/tex]

=$7x-21=4$

=$7x=25$

So our final answer would be

$x=\dfrac{25}{7}$