Question

solve for x : x^2-9/x+3=4/7​

Answer 1

Step-by-step explanation:

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Answer 2

following are the steps for getting the answer:

Given:

$\frac{ x^2-9}{x+3}=\frac{4}{7}$

To find:

value of x

Solution:

we have to find the value of x in the $\frac{ x^2-9}{x+3}=\frac{4}{7}$

so, we will solve the equation $\frac{ x^2-9}{x+3}=\frac{4}{7}$

$\frac{ x^2-9}{x+3}=\frac{4}{7}$

we will do a cross multiplication

7(x²-9)=4(x+3)

7x²-63=4x+12

we will separate the same variable

so,

7x²-4x=12+63

    7x²-4x -75=0

we get the quadratic eqaution

we will factorize the qaudratic eqaution

it will be written as

7x²-25x+21x-75=0

x(7x-25)+3(7-25)=0

x+3=0  or 7x-25

x=-3     or   x=25/7

Hence, the value of x is -3 or 25/7