Question

solve for x: x^2+x-(a+1)(a+2)=0

Answer 1

Hi ,

x² + x - ( a+ 1 ) ( a + 2 ) = 0

x² + ( a + 2 )x -( a + 1 ) x - (a + 1)(a+2)= 0

x( x + a + 2 ) -(a+ 1 )[x + a + 2 ] = 0

( x + a + 2 ) [ x - ( a + 1 ) ] = 0

x + a + 2 = 0 or x - ( a + 1 ) = 0

x = - ( a + 2 ) or x = a + 1

I hope this helps you.

:)