solve for x: x^2+x-(a+1)(a+2)=0
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Hi ,
x² + x - ( a+ 1 ) ( a + 2 ) = 0
x² + ( a + 2 )x -( a + 1 ) x - (a + 1)(a+2)= 0
x( x + a + 2 ) -(a+ 1 )[x + a + 2 ] = 0
( x + a + 2 ) [ x - ( a + 1 ) ] = 0
x + a + 2 = 0 or x - ( a + 1 ) = 0
x = - ( a + 2 ) or x = a + 1
I hope this helps you.
:)
x² + x - ( a+ 1 ) ( a + 2 ) = 0
x² + ( a + 2 )x -( a + 1 ) x - (a + 1)(a+2)= 0
x( x + a + 2 ) -(a+ 1 )[x + a + 2 ] = 0
( x + a + 2 ) [ x - ( a + 1 ) ] = 0
x + a + 2 = 0 or x - ( a + 1 ) = 0
x = - ( a + 2 ) or x = a + 1
I hope this helps you.
:)
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