solve for x x(2x+1)=6
Answers
ANSWER.
- The values of x are -2 and 1.5.
SOLUTION.
Given,
→ x(2x + 1) = 6
→ 2x² + x - 6 = 0
By splitting the middle term, we get,
→ 2x² + 4x - 3x - 6 = 0
→ 2x(x + 2) - 3(x + 2) = 0
→ (2x - 3)(x + 2) = 0
By zero product rule,
→ (2x - 3) = 0 or (x + 2) = 0
→ x = 3/2, -2
★ So, the values of x are 1.5 and -2.
LEARN MORE.
⊕ General form of a quadratic equation -
→ ax² + bx + c = 0
Here,
→ a = Coefficient of x².
→ b = Coefficient of x.
→ c = Constant term.
⊕ How to solve?
To solve a quadratic equation, we have to split the middle term and then using zero-product rule, the roots are calculated.
⊕ Sum and product of roots.
1. Sum of roots of a quadratic equation = -b/a
2. Product of roots of a quadratic equation = c/a
⊕ Nature of roots.
∅ The discriminant of a quadratic equation tells us about the nature of roots.
Discriminant (D) = b² - 4ac.
- If D > 0, roots are real and distinct.
- If D = 0, roots are equal and real.
- If D < 0, roots are imaginary.