Question

solve for x ; x √3 cot 30°+tan 60°*cosec 60°= sin 30°+2cot^2 30°+xcos^2 30°​

Answer 1

Answer:

xtan45

0

.cot60

0

=sin30

0

.csc60

0

⇒x.1.

3

1

=

2

1

×

3

2

⇒x=1

Hence, the answer is 1.

Answer 2

Step-by-step explanation:

x √3 cot 30°+tan 60°*cosec 60°= sin 30°+2cot^2 30°+xcos^2 30°

$x \sqrt{3} \: cot \: 30 \degree \: + \: tan \: 60\degree \times cosec \: 60\degree = sin \: 30\degree + 2 \: {cot}^{2} 30\degree + x {cos}^{2} 30\degree \\ x \sqrt{3} \times \sqrt{3} + \sqrt{3} \times \frac{2}{ \sqrt{3} } = \frac{1}{2} + 2 \times ({ \sqrt{3} })^{2} + x \times ({ \frac{ \sqrt{3} }{2}) }^{2} \\ 3x + 2 = \frac{1}{2} + 2 \times 3 + x \times \frac{3}{4} \\ 3x + 2 = \frac{1}{2} + 6 \: + \frac{3x}{4} \\ on \: changing \: the \: sides \\ 3x - \frac{3x}{4} = \frac{1}{2} + 6 - 2 \\ \frac{12x - 3x}{4} = \frac{1 + 12 - 4}{2} \\ \frac{9x}{4} = \frac{13 - 4}{2} \\ \frac{9x}{4} = \frac{9}{2} \\ x = \frac{9 \times 4}{2 \times 9} \\ x = 2$

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