Math, asked by ami2005, 1 year ago

solve for x : x^5÷1/x^-3 = 49​

Answers

Answered by tejasgupta
9

Answer:

7

Step-by-step explanation:

x^5 \div \dfrac{1}{x^{-3}} = 49\\\\\\\implies x^5 \times x^{-3} = 49\\\\\implies x^{5+(-3)} = 49\\\\\implies x^{5-3} = 49\\\\\implies x^2 = 49\\\\\implies x = \sqrt{49} = \boxed{\boxed{\bold{7}}}

Answered by soniatiwari214
0

Concept

The power of any two quantities which have the same base gets added when they are multiplied and similarly the power get subtracted when the two quantities with the same base are divided.

Given

The given expression which is in term of x is

x^5÷1/x^-3 = 49

Find

We have to calculate the value of x.

Solution

Since, x^5÷1/x^-3 = 49

Therefore, x^5*x^-3 = 49, since the reciprocal of a reciprocal is itself the quantity.

Hence, x^(5-3) = 49

x^2 = 49

x^2 = 7^2

Taking the square root on both side we have

x = 7

Hence the value of x is 7.

#SPJ2

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